Package net.sf.saxon.om
Class NamespaceCodeIterator
java.lang.Object
net.sf.saxon.om.NamespaceCodeIterator
- All Implemented Interfaces:
IntIterator
This class provides an iterator over the namespace codes representing the in-scope namespaces
of any node. It relies on nodes to implement the method
NodeInfo.getDeclaredNamespaces(int[])
.
The result does not include the XML namespace.
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Method Summary
Modifier and TypeMethodDescriptionboolean
hasNext()
Test whether there are any more integers in the sequencestatic IntIterator
iterateNamespaces
(NodeInfo element) Factory method: create an iterator over the in-scope namespace codes for an elementint
next()
Return the next integer in the sequence.static void
sendNamespaces
(NodeInfo element, Receiver receiver) Send all the in-scope namespaces for a node to a specified receiver
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Method Details
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iterateNamespaces
Factory method: create an iterator over the in-scope namespace codes for an element- Parameters:
element
- the element (or other node) whose in-scope namespaces are required. If this is not an element, the result will be an empty iterator- Returns:
- an iterator over the namespace codes. A namespace code is an integer that represents a prefix-uri binding; the prefix and URI can be obtained by reference to the name pool. This iterator will represent all the in-scope namespaces, without duplicates, and respecting namespace undeclarations. It does not include the XML namespace.
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sendNamespaces
Send all the in-scope namespaces for a node to a specified receiver- Parameters:
element
- the element in question (the method does nothing if this is not an element)receiver
- the receiver to which the namespaces are notified- Throws:
XPathException
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hasNext
public boolean hasNext()Description copied from interface:IntIterator
Test whether there are any more integers in the sequence- Specified by:
hasNext
in interfaceIntIterator
- Returns:
- true if there are more integers to come
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next
public int next()Description copied from interface:IntIterator
Return the next integer in the sequence. The result is undefined unless hasNext() has been called and has returned true.- Specified by:
next
in interfaceIntIterator
- Returns:
- the next integer in the sequence
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